(x^6-5x^4-x^2)/x^2

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Solution for (x^6-5x^4-x^2)/x^2 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^6-(5*x^4)-x^2)/(x^2) = 0

(x^6-5*x^4-x^2)/(x^2) = 0

(x^6-(5*x^4)-x^2)/(x^2) = 0 // * x^2

x^6-(5*x^4)-x^2 = 0

x^6-5*x^4-x^2 = 0

t_1 = x^2

1*t_1^3-5*t_1^2-1*t_1^1 = 0

t_1^3-5*t_1^2-t_1 = 0

t_1*(t_1^2-5*t_1-1) = 0

t_1^2-5*t_1-1 = 0

DELTA = (-5)^2-(-1*1*4)

DELTA = 29

DELTA > 0

t_1 = (29^(1/2)+5)/(1*2) or t_1 = (5-29^(1/2))/(1*2)

t_1 = (29^(1/2)+5)/2 or t_1 = (5-29^(1/2))/2

t_1 = 0

t_1 = 0

t_1 = (5-29^(1/2))/2

x^2-((5-29^(1/2))/2) = 0

1*x^2 = (5-29^(1/2))/2 // : 1

x^2 = (5-29^(1/2))/2

t_1 = (29^(1/2)+5)/2

x^2-((29^(1/2)+5)/2) = 0

1*x^2 = (29^(1/2)+5)/2 // : 1

x^2 = (29^(1/2)+5)/2

x^2 = (29^(1/2)+5)/2 // ^ 1/2

abs(x) = ((29^(1/2)+5)^(1/2))/(2^(1/2))

x = ((29^(1/2)+5)^(1/2))/(2^(1/2)) or x = -(((29^(1/2)+5)^(1/2))/(2^(1/2)))

t_1 = 0

x^2+0 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in { 0}

x in { ((29^(1/2)+5)^(1/2))/(2^(1/2)), -(((29^(1/2)+5)^(1/2))/(2^(1/2))) }

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